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[Blade-of-the-Moon]

Okay, I admit to being very bad at mathematics. I'm still trying to figure this out. How can I work out the size of, say, a Diabloceratops, in 1/20 scale?
How do sculptors in general work out the scale of dinosaurs? What is the formula that is used?

I tried using the scale calculator but it went over my head

Thanks

let me see if I can figure it for you.

[Blade-of-the-Moon]

Okay, I admit to being very bad at mathematics. I'm still trying to figure this out. How can I work out the size of, say, a Diabloceratops, in 1/20 scale?
How do sculptors in general work out the scale of dinosaurs? What is the formula that is used?

I tried using the scale calculator but it went over my head

Thanks

ok,

I punched in 1:20 at the top.

A Diabloceratops is 18' long = 216"  so enter 216 in the next space, I clicked inches.

The space below displays the measurement for a Diabloceratops in 1:20  scale, 10.8" .

You can also click centimeters instead.

[tyrantqueen]

Okay, I admit to being very bad at mathematics. I'm still trying to figure this out. How can I work out the size of, say, a Diabloceratops, in 1/20 scale?
How do sculptors in general work out the scale of dinosaurs? What is the formula that is used?

I tried using the scale calculator but it went over my head

Thanks

ok,

I punched in 1:20 at the top.

A Diabloceratops is 18' long = 216"  so enter 216 in the next space, I clicked inches.

The space below displays the measurement for a Diabloceratops in 1:20  scale, 10.8" .

You can also click centimeters instead.

Thanks I think I've figured it out now.

[postsaurischian]

How can I work out the size of, say, a Diabloceratops, in 1/20 scale?

1. You measure the length of the figure (skull + whole spine)
    When the Diabloceratops is fully stretched out, no problem, you can use a regular ruler.
    If the animal is curved in one way or the other you can measure it in many steps or use a string following the whole length.

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

[tyrantqueen]

How can I work out the size of, say, a Diabloceratops, in 1/20 scale?

1. You measure the length of the figure (skull + whole spine)
    When the Diabloceratops is fully stretched out, no problem, you can use a regular ruler.
    If the animal is curved in one way or the other you can measure it in many steps or use a string following the whole length.

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

Danke

[Blade-of-the-Moon]

Okay, I admit to being very bad at mathematics. I'm still trying to figure this out. How can I work out the size of, say, a Diabloceratops, in 1/20 scale?
How do sculptors in general work out the scale of dinosaurs? What is the formula that is used?

I tried using the scale calculator but it went over my head

Thanks

ok,

I punched in 1:20 at the top.

A Diabloceratops is 18' long = 216"  so enter 216 in the next space, I clicked inches.

The space below displays the measurement for a Diabloceratops in 1:20  scale, 10.8" .

You can also click centimeters instead.

Thanks I think I've figured it out now.

Glad to assist.

[Spinosaurus Aegyptiacus]

Yep, I'm always happy to offer a new piece as soon as the artist is ready.

Thanks for the support, everyone. This 3D printing to resin casting collaboration worked out very nicely with Andrew Sides; as you can see, we're both quite pleased with the results. The final piece shows all of the artist's hard work in detailing the model, which would have been lost in a lower quality Shapeways printing. Big thanks to Andrew for all his hard work!

Plenty of other goodies coming down the line. I recently received some top-secret news that would have everyone screaming, though it will be a while before it's publicly announced. I also need to find out who would support a collaborative project with Dan's Dinosaurs and Manuel Bejarano.

I confess, the suspense and long period of time with no posting is killing me...

[Dan]

[Blade-of-the-Moon]

Your killing me Dan ! Bang straight to the ole blood muscle !

[Spinosaurus Aegyptiacus]

Your killing me Dan ! Bang straight to the ole blood muscle !

I somehow knew you would be the first to comment, Blade! 

[tyrantqueen]

Looks great, but something about the head doesn't do it for me Sean Cooper is an amazing artist, of course, but I still think Shane Foulkes' allo is the best one ever made.

[Blade-of-the-Moon]

Here's another angle on it :


I believe Sean went with the newer interpretation of Allosaurus rather than just basing it on Big Al. So it has longer , larger arms and bigger more robust skull than we're used to seeing.

After seeing his work on the Concavenator I would have hoped he'd be a bit more daring..add some spines , osteoderms, ect..but those could added by a skilled customizer.

[tyrantqueen]

Yeah, I already saw the other angle on Dan's site...but my opinion is still the same. I like the sculpting on the hands and feet though.

[Spinosaurus Aegyptiacus]

I would agree w/TQ that the Shane Foulkes Allo is better-but then again, that's the king of all Allosaurus figures, so, there's that.
As far as the Sean Cooper model goes, though, I think it does a fairly good job of recreating this prehistoric killer, though I too would have liked to see a more dynamic pose and more liberties taken with things like spines, bigger crests, etc. But overall, the model is quite good.

[s.foulkes]

How can I work out the size of, say, a Diabloceratops, in 1/20 scale?

1. You measure the length of the figure (skull + whole spine)
    When the Diabloceratops is fully stretched out, no problem, you can use a regular ruler.
    If the animal is curved in one way or the other you can measure it in many steps or use a string following the whole length.

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

ITs actually 1/30th scale on the button.

[tyrantqueen]

How can I work out the size of, say, a Diabloceratops, in 1/20 scale?

1. You measure the length of the figure (skull + whole spine)
    When the Diabloceratops is fully stretched out, no problem, you can use a regular ruler.
    If the animal is curved in one way or the other you can measure it in many steps or use a string following the whole length.

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

ITs actually 1/30th scale on the button.

What about  10.8" long? Is that correct for 1/20 scale?

[postsaurischian]

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

ITs actually 1/30th scale on the button.

I'm afraid I don't understand what you're saying .
Do you say: 450 : 22 = 30 ?
Or are you saying Diabloceratops was 660 cm long?

What about  10.8" long? Is that correct for 1/20 scale?

No. That would make the Diabloceratops 216" (550 cm) long - too big.

[tyrantqueen]

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

ITs actually 1/30th scale on the button.

I'm afraid I don't understand what you're saying .
Do you say: 450 : 22 = 30 ?
Or are you saying Diabloceratops was 660 cm long?

What about  10.8" long? Is that correct for 1/20 scale?

No. That would make the Diabloceratops 216" (550 cm) long - too big.

But BotM said Diablo was 216" long:

ok,

I punched in 1:20 at the top.

A Diabloceratops is 18' long = 216"  so enter 216 in the next space, I clicked inches.

The space below displays the measurement for a Diabloceratops in 1:20  scale, 10.8" .

You can also click centimeters instead.

I am confuzzled

[Blade-of-the-Moon]

2. Let's say the result was 22 cm .
    The estimated length of Diabloceratops is 4.50 m (= 450 cm).
    450 cm : 22 cm = 20.45
    The figure is about 1:20.

ITs actually 1/30th scale on the button.

I'm afraid I don't understand what you're saying .
Do you say: 450 : 22 = 30 ?
Or are you saying Diabloceratops was 660 cm long?

What about  10.8" long? Is that correct for 1/20 scale?

No. That would make the Diabloceratops 216" (550 cm) long - too big.

But BotM said Diablo was 216" long:

ok,

I punched in 1:20 at the top.

A Diabloceratops is 18' long = 216"  so enter 216 in the next space, I clicked inches.

The space below displays the measurement for a Diabloceratops in 1:20  scale, 10.8" .

You can also click centimeters instead.

I am confuzzled

You ain't the only one. 

[postsaurischian]

But BotM said Diablo was 216" long:

216" = 5.5 m
The Princeton Field Guide to Dinosaurs p.258 says 4.5 m.
Who's right? Blade or Gregory?